Understanding |
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represents the height of the rectangular solid and represents the base area. Thus . |
Given a closed bounded region and continuous functions on , and suppose that on . Then the volume of solid bounded by the lines parallel to -axis through the boundary and the surfaces is given by
SOLUTION Projection of the solid bounded by two cylinders onto -plane is and . Thus, . Also implies . Thus the upper surface is and the lower surface is over . From this, the volume of the solid is set up by , where represents the small rectangle of base area and represents the height of a small solid cylinder. Now use vertically simple region for . Then
Take a point in and evaluate the value of to find out which surfaces upper or lower surface.
Exercise5-8 |
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SOLUTION Note that the solid is bounded by the surface goes through the boundary of and parallel to the -axis, and the plane , . Using the polar coordinate to express . Since ,
The limit of integration is constant, we can express the double integral as the product of two single integral.
(a) The region enclosed by
(b) Inside of the curve and outside of the curve .
(c) Inside of the curve and outside of the curve
(a) with , .
(b) with .
(c) with .
(a) with
(b) with
(a) Sphere with the radius .
(b) with
(c) and .
(d) The surface generated by rotating about -axis for .
(a) with
(b) .
(c) and .
(d) and , .