不定積分(indefinite integrals)

確認問題

1.
次の積分を求めよう.

(a) $\displaystyle{\int (2x-3) dx }$ (b) $\displaystyle{\int 5x^{4} dt}$ (c) $\displaystyle{\int \sqrt[3]{x^{2}} dx}$ (d) $\displaystyle{\int \frac{1}{\sqrt{x}} dx}$

(e) $\displaystyle{\int \frac{\sin{x}}{\cos{x}} dx}$ (f) $\displaystyle{\int \frac{1}{\cos^{2}x} dx}$ (g) $\displaystyle{\int \sin^{2}{x} dx}$ (h) $\displaystyle{\int \frac{1}{x^{2} - 4} dx}$

(i) $\displaystyle{\int \frac{1}{x^{2}+4}dx }$

演習問題

1.
次の積分を求めよう.

(a) $\displaystyle{\int (3x^{-3} + 4x^{5}) dx }$ (b) $\displaystyle{\int (t^{3}+ \frac{1}{t^{2}+1}) dt}$ (c) $\displaystyle{\int -2\tan^{2}{x} dx}$

(d) $\displaystyle{\int \frac{x^{3} + 1}{\sqrt{x}} dx}$ (e) $\displaystyle{\int \frac{x^{2} + 5}{x^{2} + 4} dx}$ (f) $\displaystyle{\int \frac{1}{\sqrt{4 - t^{2}}} dt}$ (g) $\displaystyle{\int \cos^{2}{x} dx}$

(h) $\displaystyle{\int \frac{1}{\sqrt{t^{2} + 4}} dt}$ (i) $\displaystyle{\int \frac{1}{4 - x^{2}}dx }$